Then if you know what the OP meant why did you ask?

because they made a nonsensical claim that doesn't align with my (and likely their) understanding of what the FT is and does.

The FT is _NOT_ just a convolution, but under certain conditions a specific operation on FT terms is equivalent to a convolution.

I didn't know what they meant. There are so many FFT tricks. I was hoping this was another.